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Home/ Questions/Q 976791
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T03:48:10+00:00 2026-05-16T03:48:10+00:00

I want to write a implicit conversion of Tuple2[A,B] to Seq[C] where C is

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I want to write a implicit conversion of Tuple2[A,B] to Seq[C] where C is super type of both A and B.
My first try as following:

implicit def t2seq[A,B,C](t: (A,B))(implicit env: (A,B) <:< (C,C)): Seq[C] = {
    val (a,b) = env(t)
    Seq(a,b)
}

But it doesn’t work:

scala> (1,2): Seq[Int]
<console>:7: error: type mismatch;
 found   : (Int, Int)
 required: Seq[Int]
       (1,2): Seq[Int]
       ^

While this one works:

class Tuple2W[A,B](t: (A,B)) {
    def toSeq[C](implicit env: (A,B) <:< (C,C)): Seq[C] = {
        val (a,b) = env(t)
        Seq(a,b)
    }
}
implicit def t2tw[A,B](t: (A,B)): Tuple2W[A,B] = new Tuple2W(t)

Use case:

scala> (1,2).toSeq
res0: Seq[Int] = List(1, 2)

I have no idea why the first solution didn’t work as expected.
Scala version 2.8.0.r22634-b20100728020027 (Java HotSpot(TM) Client VM, Java 1.6.0_20).

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  1. Editorial Team
    Editorial Team
    2026-05-16T03:48:10+00:00Added an answer on May 16, 2026 at 3:48 am

    You only need to use <:< if the parameters to be restricted are already bound in the surrounding scope (as they are in your second try), so in your case

    implicit def t2seq[A <: C,B <: C,C](t: (A,B)) = Seq(t._1, t._2)
    

    is sufficient.

    I would guess that your first try did not work as it is too complex for the type inferencer.

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