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Home/ Questions/Q 7550565
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T10:14:42+00:00 2026-05-30T10:14:42+00:00

I want to write a PHP script which will first detect URL’s and see

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I want to write a PHP script which will first detect URL’s and see if they have sub dir or not, if they are simple URL like site.com then it would write 1 in one of the DB’s table but if the URL is something like this site.com/images or site.com/images/files then it should’nt do the query..

EDIT: Answer by Mob it works but doesnt work if there are more than one url

 $url = "http://lol.com";
 $v = parse_url($url);

 if (isset( $v['path']) && (!empty($v['path'])) && ($v['path'] != "/") ){
 echo "yeah";
 } else { 
 echo "nah";
 }
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T10:14:43+00:00Added an answer on May 30, 2026 at 10:14 am

    Use parse_url

    $url = "http://lol.com";
    $v = parse_url($url);
    
    if (isset( $v['path']) && (!empty($v['path'])) && ($v['path'] != "/") ){
           echo "yeah";
       } else { 
           echo "nah";
       }
    

    EDIT:

    To parse multiple urls;

    • Store the urls in an array.
    • Use a loop to iterate over the array while passing the values to a function that performs the check

    Here:

    <?php
    
    
    $arr = array("http://google.com",
                 "http://google.com/image/",
                 "http://flickr.com",
                 "http://flickr.com/image" );
    
    foreach ($arr as $val){
        echo $val."       ". check($val)."\n";
    }
    
    function check ($url){
    $v = parse_url($url);
    
    if (isset( $v['path']) && (!empty($v['path'])) && ($v['path'] != "/") ){
               return "true";
           } else { 
               return "false";
           }
    }
        ?>
    

    The output is :

    http://google.com              false
    http://google.com/image/       true
    http://flickr.com              false
    http://flickr.com/image        true
    
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