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Home/ Questions/Q 7872187
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T02:08:01+00:00 2026-06-03T02:08:01+00:00

i want to write a plugin which will pass a variable stored as input(which

  • 0

i want to write a plugin which will pass a variable stored as input(which is an image) id to the form on clicking the input image or by any other method

=========================================================================================

<?php
echo $_POST['id'];
?>

<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Kunfu Panda</title>
<link href="css/main.css" rel="stylesheet" type="text/css" media="projection,screen" />
</head>
<body>
    <div class="wrapper" >
        <form action="panda.php" method="post" class="openid_provider" />
             <input type="image" src="images/google_button.png" id="google" /> 
         </form>    
  </div>
<script type="text/javascript" src="js/test.js"></script>
<script type="text/javascript" src="js/jquery-ui-1.8.19.custom.min.js"></script>
<script type="text/javascript">  
$(document).ready(function(){
    $('form').openid(); 
})
</script>
</body>
</html>

===============================================================================

my plugin is openid (test,js)

(function($){
    $.fn.openid = function() {
        $('input').click(function(){
        var provider = $(this).attr('name');
        $(this).submit(provider);   
        })
        }
})(jQuery);

now the form is getting submitted on click on google image which is an input with id “google” but the form action which is the same page is not able to recognise the $_POST[‘provider’] variable

please help me out.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T02:08:02+00:00Added an answer on June 3, 2026 at 2:08 am

    Try this:

    <?php
      var_dump($_POST);
    ?>
    
    <head>
      <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
      <title>Kunfu Panda</title>
      <link href="css/main.css" rel="stylesheet" type="text/css" media="projection,screen" />
      <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.js"></script>
      <script type="text/javascript" src="https://ajax.googleapis.com/ajax/libs/jqueryui/1.8.18/jquery-ui.js"></script>
      <script type="text/javascript" src="js/test.js"></script>
    </head>
    <body>
      <div class="wrapper" >
        <form action="panda.php" method="post" class="openid_provider" />
          <input type="image" src="images/google_button.png" id="google"/> 
        </form>
      </div>
    </body>
    <script type="text/javascript">  
      $(document).ready(function(){
        $('form').openid(); 
      })
    </script>
    

    js:

    (function($){
      $.fn.openid = function() {
        $('input').click(function(e){
          var provider = $(this).attr('id');  //get id
          var myinput = $('<input type="hidden" name="provider"/>').val(provider);
          $('form').append(myinput);
          $('form').submit();
        })
      }
    })(jQuery);
    
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