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Home/ Questions/Q 5996179
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Editorial Team
  • 0
Editorial Team
Asked: May 23, 20262026-05-23T00:03:59+00:00 2026-05-23T00:03:59+00:00

I want to write a program which can: when I enter, say Alan Turing

  • 0

I want to write a program which can:
when I enter, say “Alan Turing“, it outputs “Turing, A“.
But for my following program, it outputs “uring, A“, I thought for long but failed to figure out where T goes.
Here is the code:

#include <stdio.h>
int main(void)
{
char initial, ch;

//This program allows extra spaces before the first name and between first name and second name, and after the second name.

printf("enter name: ");

while((initial = getchar()) == ' ')
    ;

while((ch = getchar()) != ' ')  //skip first name
    ;

while ((ch = getchar()) == ' ')
{
    if (ch != ' ')
        printf("%c", ch);  //print the first letter of the last name
}
while((ch = getchar()) != ' ' && ch != '\n')
{
    printf("%c", ch);
}
printf(", %c.\n", initial);

return 0;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-23T00:04:00+00:00Added an answer on May 23, 2026 at 12:04 am

    Your bug is here:

    while ((ch = getchar()) == ' ')
    {
        if (ch != ' ')
            printf("%c", ch);  //print the first letter of the last name
    }
    while((ch = getchar()) != ' ' && ch != '\n')
    {
        printf("%c", ch);
    }
    

    The first loop reads characters until it finds a non-space. That’s your ‘T’. Then the second loop overwrites it with the next character, ‘u’, and prints it.
    If you switch the second loop to a do {} while(); it should work.

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