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Editorial Team
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Editorial Team
Asked: June 9, 20262026-06-09T19:03:28+00:00 2026-06-09T19:03:28+00:00

I want to write a spring command line program that is initialized with a

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I want to write a spring command line program that is initialized with a property file which is passed as command line parameter. How can that be done?

Starting class:

public static void main (String [] args) {
    String configFilename = args[0];
    ApplicationContext ctx = new ClassPathXmlApplicationContext(
        "classpath:/context/applicationContext.xml");
    MyBean bean = ctx.getBean(MyBean.class); 
    bean.getStarted();
}

applicationContext.xml:

<context:property-placeholder location="CONFIGFILENAME" ignore-unresolvable="true"/>

How do I get the config file name over from my main method to the actual spring context so that I can load the correct environment dependent properties?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-09T19:03:29+00:00Added an answer on June 9, 2026 at 7:03 pm

    In your case, you could better set a system property for properties file location

    System.getProperties().setProperty("location", args[0]);
    

    Then in applicationContext.xml file

    <context:property-placeholder location="${location}" ignore-unresolvable="true"/>  
    

    Hope this will solve your problem.

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