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Home/ Questions/Q 8716389
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Editorial Team
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Editorial Team
Asked: June 13, 20262026-06-13T06:04:02+00:00 2026-06-13T06:04:02+00:00

i want to write a urldecode template filter and i have a template tag

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i want to write a urldecode template filter and i have a template tag folder under my app with the following code :

from django import template
from urllib import unquote

register = template.Library()

@register.filter
def unquote(value):
    return unquote(value)

class SetVarNode(template.Node):

    def __init__(self, var_name, var_value):
        self.var_name = var_name
        self.var_value = var_value

    def render(self, context):
        try:
            value = template.Variable(self.var_value).resolve(context)
        except template.VariableDoesNotExist:
            value = ""
        context[self.var_name] = value
        return u""

@register.tag(name='set')
def set_var(parser, token):
    """
        {% set <var_name>  = <var_value> %}
    """
    parts = token.split_contents()
    if len(parts) < 4:
        raise template.TemplateSyntaxError("'set' tag must be of the form:  {% set <var_name>  = <var_value> %}")
    return SetVarNode(parts[1], parts[3])

then i am calling my registed filter in my template like this :

kmz.file|unquote

Any ideas why?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-13T06:04:03+00:00Added an answer on June 13, 2026 at 6:04 am

    It’s because you import unquote and then redefine it.

    Use this instead:

    from urllib import unquote as unquote_old
    
    @register.filter
    def unquote(value):
        return unquote_old(value) 
    

    or

    from urllib import unquote
    
    @register.filter
    def unquote_new(value):
        return unquote(value)
    
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