Question

I want to write a vb or bat script that goes through a file and finds and replaces any quotation mark not followed or proceeded by a comma with a double quote.

Edit: solved

Ok so I got it I needed to use back references.

Incase anyone else needs something similar here is a little example script replacing ” not followed or proceed by a comma with Doubleqoute

dim rp, file
set re = new RegExp

re.Pattern="([^,])("")([^,])"
re.Global=True
s="It is alive ""IT IS ALIVE"","

MsgBox re.Replace(s,"$1 DoubleQuote $3")

Answer 1

Ok so I got it I needed to use back references.

Incase anyone else needs something similar here is a little example script replacing ” not followed or proceed by a comma with Doubleqoute

dim rp, file
set re = new RegExp

re.Pattern="([^,])("")([^,])"
re.Global=True
s="It is alive ""IT IS ALIVE"","

MsgBox re.Replace(s,"$1 DoubleQuote $3")

EDIT: Also the above does not work with one letter words in order to make it work with one letter you have to use look forward and look back functions.