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Home/ Questions/Q 1084015
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T22:30:30+00:00 2026-05-16T22:30:30+00:00

I want user to work with only one order connected to user’s session. So

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I want user to work with only one order connected to user’s session. So I set singular resource for order

routes.rb:

resource :order

views/orders/new.html.erb:

<%= form_for @order do |f| %>
   ...
<% end %>

But when I open the new order page I get an error:

undefined method `orders_path`

I know, that I can set :url => order_path in form_for, but what is the true way of resolving this collision?

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  1. Editorial Team
    Editorial Team
    2026-05-16T22:30:31+00:00Added an answer on May 16, 2026 at 10:30 pm

    Unfortunately, this is a bug. You’ll have to set the url like you mention.

    = form_for @order, :url => order_path do |f|
    

    Note that this will properly route to create or update depending on whether @order is persisted.


    Update

    There’s another option now. You can add this to your routes config:

    resolve("Order") { [:order] }
    

    Then when the polymorphic_url method is given an object with class name "Order" it will use [:order] as the url component instead of calling model_name.route_key as described in jskol’s answer.

    This has the limitation that it cannot be used within scopes or namespaces. You can route a namespaced model at the top level of the routes config:

    resolve('Shop::Order') { [:shop, :order] }
    

    But it won’t have an effect on routes with extra components, so

    url_for(@order)           # resolves to shop_order_url(@order)
    url_for([:admin, @order]) # resolves to admin_shop_orders_url(@order) 
                              #        note plural 'orders' ↑
                              #        also, 'shop' is from module name, not `resolve` in the second case
    
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