Question

I want with a given double number to return its “size” (known as |number|, or number of digit without the numbers after the dot), for example:

12.324654 -> 2
12 -> 2
0.99 -> 0
1.01 -> 1
901 -> 3
-0.99 -> 0
-9.999 -> 1

There must be a function is .net that I dont familiar with that does it..

Thanks.

Answer 1

((int)Math.Abs(12.324654)).ToString().Length

Math.Abs will convert to positive number (don’t want to count the negative sign)
(int) will drop the digits following the decimal point
ToString() converts to a string ===> “12”
Length tells you how many characters there are
there is an edge case where (int)( some number ) == 0, where the length is going to give you 1– you may not want this, so be aware of the possibility

now, what you COULD do is make this an extention method….

public static class Utils
{
   public static int Size(this double n)
   {
     int i = (int)Math.Abs(n);
     if ( i == 0 ) return 0;
     return  i.ToString().Length;
   }
}

12.324654.Size() == 2;