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Home/ Questions/Q 7706315
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Editorial Team
  • 0
Editorial Team
Asked: June 1, 20262026-06-01T00:05:45+00:00 2026-06-01T00:05:45+00:00

I want write a little code analyzer which parses nested structures and translates into

  • 0

I want write a little code analyzer which parses nested structures and translates into valid CSS. However, I did’t get to keep the identifiers that are inherited from upper level.

The nested structure:

#foo {
    border: 1px;
    a {
        border: 2px;
    }
    b {
        border: 3px;
        c {
            border: 4px; /* comment */
        }
    }
}

I want to translate the structure into:

#foo {
    border: 1px;
}

#foo a {
    border: 2px;
}

#foo b {
    border: 3px;
}

#foo b c {
    border: 4px; /* comment */
}

Parse code:

#include <iostream>
#include <iterator>
#include <string>

using namespace std;

int main() {

    string str = "\
    #foo {\
        border: 1px;\
        a {\
            border: 2px;\
        }\
        b {\
            border: 3px;\
            c {\
                border: 4px; /* comment */\
            }\
        }\
    }";

    string::const_iterator i = str.end(),
    begin = str.begin(), end;

    while (i != begin) {
        if (*i == ';' || (*i == '/' && *(i-1) == '*')) {
            end = i++;

            while (*i-- != '{');

            while (true) {
                if (*i == ';' || *i == '}' || *i == '{' || i == begin)
                    break;
                i--;
            }

            string item(++i, ++end);
            cout << item << "}" << endl;
        }
        i--;
    }

    return 0;
}

Out:

c {
    border: 4px; /* comment */
}

b {
    border: 3px;
}

a {
    border: 2px;
}

#foo {
    border: 1px;
}

So, how to keep the identifiers that are inherited from upper level?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-01T00:05:46+00:00Added an answer on June 1, 2026 at 12:05 am

    If you’re using c++, why not use OO?

    Create a class that represents a scope (a matched {} pair), which has a list of pointers to it’s child scopes and a pointer to its parent scope: ie: from your example foo’s list contains a and b, b’s list contains c.

    When printing out, recursively go into each leaf scope, then get it to print its ‘full’ name by adding the names of all its ‘ancestors’ onto the beginning of its own.

    A skeleton starting point:

    class Element
    {
    public:
        Element()
        : m_pParent( 0 )
        {
        }
    
    
    private:
    
        std::string m_Name;
        std::string m_Contents;
    
        Element* m_pParent;
        std::list<Element*> m_Children;
    
    };
    
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