Question

I wanted to know if there was a way to do an IF ELSE statement within SQL syntax or if someone could help me with CASE. Basically if a file name (string) is found in the file_url column then change where I want to use secondary information. I hope my example can help further explain what I am trying to do.

    $sql = "SELECT vm.file_url FROM #__virtuemart_medias AS vm 
        INNER JOIN #__virtuemart_product_medias AS pm ON vm.virtuemart_media_id = pm.virtuemart_media_id 
        WHERE pm.virtuemart_product_id = {$product_id} ";

    $result = mysql_query($sql); 
    $row = mysql_fetch_array($result); 
    $FILEURL = $row["vm.file_url"];  
    if ($FILEURL == "thumb_phone01.jpg"){       
            $sql .= "AND pm.ordering = 2";
    }
    else {
        $sql .= "AND pm.ordering = 1";
        }
            $this->_db->setQuery($sql);
            $img = $this->_db->LoadResult();
            return $img;
        }

Thank you.

Answer 1

One option would be to use CASE and REGEXP:

SELECT vm.file_url FROM #__virtuemart_medias AS vm 
    INNER JOIN #__virtuemart_product_medias AS pm 
            ON vm.virtuemart_media_id = pm.virtuemart_media_id 
    WHERE pm.virtuemart_product_id = {$product_id}
         AND pm.ordering = CASE 
                             WHEN vm.file_url  REGEXP 'thumb_phone01.jpg' 
                                THEN 2 
                                ELSE 1 
                             END

Here is the SQL Fiddle.

Good luck.