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Home/ Questions/Q 7944569
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T00:35:28+00:00 2026-06-04T00:35:28+00:00

I wanted to make a window and add a QTabWidgets with the widgets I

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I wanted to make a window and add a QTabWidgets with the widgets I want to it. So I followed the Qt TabDialog example and from what I know, I followed the same path as in the example.
Problem is I get this error while trying to add my widgets as tabs: “/home/user/Programming/C++/QtTests/TabExample/TabExample-build-desktop-Desktop_Qt_4_8_1_for_GCC__Qt_SDK__Release/../TabExample/tabwidget.cpp:20: error: no matching function for call to ‘QTabWidget::addTab(Tab_One*, QString*&)'”. Why do I get this error because Tab_One is inherited from QWidget? Here is my main widget code:

Header file:

#ifndef TABWIDGET_H
#define TABWIDGET_H

#include <QWidget>

class QTabWidget;
class Tab_One;
class Tab_Two;
class QString;
class QHBoxLayout;
class QDialog;

class TabDialog : public QDialog {
    Tab_One *firstTab;
    Tab_Two *secondTab;
    QTabWidget *myTabWidget;
    QString *labelTabOne;
    QString *labelTabTwo;
    QHBoxLayout *layout;
public:
    TabDialog(QWidget *parent = NULL);
};

#endif // TABWIDGET_H

and source file:

#include <QWidget>
#include <QDialog>
#include <QTabWidget>
#include <QHBoxLayout>
#include <QString>

#include "tabwidget.h"
#include "tab1.h"
#include "tab2.h"

TabDialog::TabDialog(QWidget *parent) : QDialog(parent)
{
    layout = new QHBoxLayout;

    labelTabOne = new QString("My First Tab");
    labelTabTwo = new QString("My Second Tab");

    myTabWidget = new QTabWidget;

    firstTab = new Tab_One;
    secondTab = new Tab_Two;

    myTabWidget->addTab(firstTab, labelTabOne);
    myTabWidget->addTab(secondTab, labelTabTwo);

    layout->addWidget(myTabWidget);
    setLayout(layout);
}

and here is one of my widets(tab1):
header:

#ifndef TAB1_H
#define TAB1_H

#include <QWidget>
class QVBoxLayout;
class QPushButton;

class Tab_One : public QWidget {
    QPushButton *button_one;
    QPushButton *button_two;
    QVBoxLayout *layout;

public:
    Tab_One(QWidget *parent = NULL);
};

#endif // TAB1_H

and source:

#include <QWidget>
#include <QDialog>
#include <QTabWidget>
#include <QHBoxLayout>
#include <QString>

#include "tabwidget.h"
#include "tab1.h"
#include "tab2.h"

TabDialog::TabDialog(QWidget *parent) : QDialog(parent)
{
    layout = new QHBoxLayout;

    labelTabOne = new QString("My First Tab");
    labelTabTwo = new QString("My Second Tab");

    myTabWidget = new QTabWidget;

    myTabWidget->addTab(new Tab_One(this), labelTabOne);
    myTabWidget->addTab(new Tab_Two(this), labelTabTwo);

    layout->addWidget(myTabWidget);
    setLayout(layout);
}

Thank you very much and sorry for the long post

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-04T00:35:30+00:00Added an answer on June 4, 2026 at 12:35 am

    The problem isn’t your tab, but the QString. QTabWidget::addTab() expects a const reference to a QString, but you’re giving it a pointer to a QString. Try using the dereference operator (*), like this:

    myTabWidget->addTab(firstTab, *labelTabOne);
    myTabWidget->addTab(secondTab, *labelTabTwo);
    
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