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Home/ Questions/Q 7860299
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Editorial Team
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Editorial Team
Asked: June 2, 20262026-06-02T22:13:57+00:00 2026-06-02T22:13:57+00:00

I was a bit surprised finding out this feature in C++, and I didn’t

  • 0

I was a bit surprised finding out this feature in C++, and I didn’t expect it to happen.

Here is the code:

struct XY {
    int x,y;
    XY(int v) : x(v), y(v) {}
};

bool test1(const XY &pos){
    return pos.x < pos.y;
}
bool test1(int x, int y){
    return x < y;
}
void functest(){
    int val = 5;
    test1(val);
}

So I can call a function with integer parameter, whether or not such overload exists, it will use the XY type function because it has a constructor of that same type! I don’t want that to happen, what can I do to prevent this?

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  1. Editorial Team
    Editorial Team
    2026-06-02T22:13:58+00:00Added an answer on June 2, 2026 at 10:13 pm

    Make the XY constructor explicit:

    explicit XY(int v) : x(v), y(v) {}
    

    This will disallow implicit conversions from int to XY, which is what is happening when you call the single-parameter test1 function.

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