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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T03:27:56+00:00 2026-05-20T03:27:56+00:00

I was about ready to start giving a jqgrid in a django app greater

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I was about ready to start giving a jqgrid in a django app greater functionality (pagination, searching, etc). In order to do this it looks as though jqgrid sends its parameters in the GET to the server. I plan to write an urlpattern to pull out the necessary stuff (page number, records per page, search term, etc) so I can pass it along to my view to return the correct rows to the grid. Has anyone out there already created this urlpattern I am in search of?

Thanks much.

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  1. Editorial Team
    Editorial Team
    2026-05-20T03:27:57+00:00Added an answer on May 20, 2026 at 3:27 am

    The answer to this was simpler than I realized. As stated in Chapter 7 of the djangobook in the section titled “Query string parameters” one can simply do something as follows, where “someParam” is the parameter in the query string you want to retrieve. However, Django is designed to be clean in that address bar at the top of the page so you should only use this option if you must.

    The query string might look something like this.

    http://somedomainname.com/?someString=1
    

    The view might look like this.

    def someView(request):
        if 'someParam' in request.GET and request.GET['someParam']:
            someParam = request.GET['someParam']
    

    Hopefully this is of some help to someone else down the road.

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