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Home/ Questions/Q 4124970
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Editorial Team
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Editorial Team
Asked: May 20, 20262026-05-20T23:48:32+00:00 2026-05-20T23:48:32+00:00

I was about to build my own IEnumerable class that performs some action on

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I was about to build my own IEnumerable class that performs some action on all items the first time something iterates over it then I started wondering, does the framework already have something that I could use?

Here’s what I was building so you have an idea what I’m looking for:

public class DelayedExecutionIEnumerable<T> : IEnumerable<T>
{
    IEnumerable<T> Items;
    Action<T> Action;
    bool ActionPerformed;

    public DelayedExecutionIEnumerable(IEnumerable<T> items, Action<T> action)
    {
        this.Items = items;
        this.Action = action;
    }

    void DoAction()
    {
        if (!ActionPerformed)
        {
            foreach (var i in Items)
            {
                Action(i);
            }
            ActionPerformed = true;
        }
    }

    #region IEnumerable<IEntity> Members

    public IEnumerator<T> GetEnumerator()
    {
        DoAction();
        return Items.GetEnumerator();
    }

    #endregion

    #region IEnumerable Members

    System.Collections.IEnumerator System.Collections.IEnumerable.GetEnumerator()
    {
        DoAction();
        return Items.GetEnumerator();
    }

    #endregion
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-20T23:48:33+00:00Added an answer on May 20, 2026 at 11:48 pm

    Iterators and yield allows you to easily create your own lazy enumerator sequence.

    Also in your case, you could easily abuse Select method of LINQ.

    items.Select(i=>{DoStuff(i); return i;});
    

    Maybe wrapping it up?

    public static IEnumerable<T> DoStuff<T>(this IEnumerable<T> items, Action<T> doStuff)
    {
        return items.Select(i=>{doStuff(i); return i;});
    }
    

    (hand-written not tested code, use with caution)

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