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Editorial Team
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Editorial Team
Asked: June 16, 20262026-06-16T05:23:48+00:00 2026-06-16T05:23:48+00:00

I was always assuming that the following test will always succeed for finite values

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I was always assuming that the following test will always succeed for finite values (no INF, no NAN) of somefloat:

assert(somefloat*0.0==0.0);

In Multiply by 0 optimization it was stated that double a=0.0 and double a=-0.0 are not strictly speaking the same thing.

So I was wondering whether this can lead to problems on some platforms e.g. can the result of the above test depend on a beeing positive or negative.

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  1. Editorial Team
    Editorial Team
    2026-06-16T05:23:50+00:00Added an answer on June 16, 2026 at 5:23 am

    If your implementation uses IEEE 754 arithmetic (which most do), then positive and negative zero will compare equal. Since the left-hand side of your expression can only be either positive or negative zero for finite a, the assertion will always be true.

    If it uses some other kind of arithmetic, then only the implementor, and hopefully the implementation-specific documentation, can tell you. Arguably (see comments) the wording of the standard can be taken to imply that they must compare equal in any case, and certainly no sane implementation would do otherwise.

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