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Home/ Questions/Q 678915
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T01:12:08+00:00 2026-05-14T01:12:08+00:00

I was browsing for an alternative to using so many shared_ptrs, and found an

  • 0

I was browsing for an alternative to using so many shared_ptrs, and found an excellent reply in a comment section:

Do you really need shared ownership?
If you stop and think for a few
minutes, I’m sure you can pinpoint one
owner of the object, and a number of
users of it, that will only ever use
it during the owner’s lifetime. So
simply make it a local/member object
of the owners, and pass references to
those who need to use it.

I would love to do this, but the problem becomes that the definition of the owning object now needs the owned object to be fully defined first. For example, say I have the following in FooManager.h:

class Foo; 
class FooManager
{
    shared_ptr<Foo> foo;
    shared_ptr<Foo> getFoo() { return foo; }
};

Now, taking the advice above, FooManager.h becomes:

#include "Foo.h"
class FooManager
{
    Foo foo;
    Foo& getFoo() { return foo; }
};

I have two issues with this. First, FooManager.h is no longer lightweight. Every cpp file that includes it now needs to compile Foo.h as well. Second, I no longer get to choose when foo is initialized. It must be initialized simultaneously with FooManager. How do I get around these issues?

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  1. Editorial Team
    Editorial Team
    2026-05-14T01:12:08+00:00Added an answer on May 14, 2026 at 1:12 am

    You can use a shared_ptr ( or any smart pointer, or even a dumb pointer) but not have shared ownership.

    E.g.

    class Foo; 
    class FooManager
    {
      private:
        shared_ptr<Foo> foo;
      public:
        Foo& getFoo() { return *foo; }
    };
    

    (This is just a sketch – you still need a setFoo(), and perhaps getFoo() should return a Foo *. But the point is that you’re back to being lightweight, and you can control when foo is created.)

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