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Editorial Team
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Asked: 2026-05-26T17:12:40+00:00

I was creating a opengl android application. I was trying to render a opengl

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I was creating a opengl android application. I was trying to render a opengl object with vertices more than 50,000. 

float itemVerts [] = {
// f 231/242/231 132/142/132 131/141/131
0.172233487787643f, -0.0717437751698985f, 0.228589675538813f,
0.176742968653347f, -0.0680393472738536f, 0.2284149434494f,
0.167979223684599f, -0.0670168837233226f, 0.24286384937854f,
// f 131/141/131 230/240/230 231/242/231
0.167979223684599f, -0.0670168837233226f, 0.24286384937854f,
0.166391290343292f, -0.0686544011752973f, 0.241920432968569f,......

and many more…. But when i do this in a function or constructor i get a error while compiling that The code of method () is exceeding the 65535 bytes limit. So I was wondering if there is a different way to do this.

I tried storing the value in file and reading it back. But the IO operation, with string parsing of such huge record is very slow. Takes more than 60 sec. Which is not good.

Please let me know if there is any other way to do this. Thank you for your time and help.

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1 Answer

  1. Editorial Team

    But when i do this in a function or constructor i get a error while
    compiling that The code of method () is exceeding the 65535 bytes
    limit. So I was wondering if there is a different way to do this.

    Put it outside the constructor (as a class variable or field)? If this doesn’t change, just make it a constant. If it does change, make it a constant anyway and copy it in the constructor.

    I tried storing the value in file and reading it back. But the IO
    operation, with string parsing of such huge record is very slow. Takes
    more than 60 sec. Which is not good.

    If you do decide to keep it in an external file and read it in, don’t read it as a string, just serialize it somehow (Java serialization, Protocol Buffers, etc.).

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