Question

i was dealing with the following code,& got confused,please have a look at it

#include<iostream>
#include<conio.h>
#include<string.h>

using namespace std;

void Xhandler(int test) throw(char,double)  /*i am restricting an integer exception     here by not including it in the argument list of throw*/
{
if(test==0) throw test;
if(test==1) throw 'a';
if(test==2) throw 123.23;
}

int main()
{
cout<"start";

try{
    Xhandler(0);  
}

catch(int i)  /*this catch statement must be ignored then,but it is running*/
{
    cout<<"caught an integer"; /*this is the output on the screen*/
}
catch(char c)
{
    cout<<"caught character";
}
catch(double a)
{
    cout<<"caught double";
}

cout<<"end";
    _getch();
    return 0;

     }

the catch statement corresponding to int must be ignored(which is not ignored) & program must have to be terminated as there is no matching catch statement left,but it is not so?

Answer 1

You did not specified the compiler. If you are using Microsoft visual C++ there is a note at Exception Specifications page on the MSDN

Visual C++ departs from the ANSI Standard in its implementation of exception specifications. The following table summarizes the Visual C++ implementation of exception specifications:

…

throw(type) – The function can throw an exception of type type. However, in Visual C++ .NET, this is interpreted as throw(…).

When using g++ the process is terminated due unexpected exception when running your example.