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Asked: May 11, 20262026-05-11T01:52:50+00:00 2026-05-11T01:52:50+00:00

I was debugging something and discovered some strangeness in JavaScript: alert(1==”) ==> false alert(0==”)

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I was debugging something and discovered some strangeness in JavaScript:

alert(1=='') ==> false alert(0=='') ==> true alert(-1=='') ==> false 

It would make sense that an implied string comparison that 0 should = ‘0’. This is true for all non-zero values, but why not for zero?

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  1. 2026-05-11T01:52:50+00:00Added an answer on May 11, 2026 at 1:52 am

    According to the Mozilla documentation on Javascript Comparison Operators

    If the two operands are not of the same type, JavaScript converts the operands then applies strict comparison. If either operand is a number or a boolean, the operands are converted to numbers; if either operand is a string, the other one is converted to a string

    What’s actually happening is that the strings are being converted to numbers. For example:

    1 == '1' becomes 1 == Number('1') becomes 1 == 1: true

    Then try this one: 1 == '1.' becomes 1 == Number('1.') becomes 1 == 1: true If they were becoming strings, then you’d get '1' == '1.', which would be false.

    It just so happens that Number('') == 0, therefore 0 == '' is true

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