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Editorial Team
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Asked: 2026-06-15T10:16:42+00:00

I was developed one application using grails 1.3.7 version. where i was using regex

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I was developed one application using grails 1.3.7 version. where i was using regex expression for password validation.

like..

 public static final String MYFAX_PASSWORD_REGEX_PATTERN = "[a-zA-Z0-9!@#\$%^&*()<>{};:.\\]\\[]{4,20}"

and it’s working fine but when i am upgrading this project into grails 2.x then its’ display me below compilation error.

Can anybody help me?

illegal escape character
public static final java.lang.String MYFAX_PASSWORD_REGEX_PATTERN = "[a-zA-Z0-9!@#$%^&*()<>{};:.\]\[]{4,20}";
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1 Answer

  1. Editorial Team

    You can try the Groovy ~"pattern" expression: 

    def MYFAX_PASSWORD_REGEX_PATTERN = ~/[a-zA-Z0-9!@#$%^&*()<>{};:.\]\[]{4,20}/

    For more information refer to the Groovy Regular Expressions manual.

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