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Home/ Questions/Q 7891603
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T06:39:38+00:00 2026-06-03T06:39:38+00:00

I was developing the below class.. public class Test1 { public void method(Object o)

  • 0

I was developing the below class..

public class Test1 
{
    public void method(Object o)
    {
        System.out.println("Object Verion");
    }   
    public void method(String s)
    {
        System.out.println("String Version");
    }



    public static void main(String args[])
    {
        Test1 question = new Test1();
        //question.method(question);

        question.method(null);
    }

}

Now upon executing it invokes string version as output So please advise here string is treated as null and what should we pass to invoke the object version.Thanks in advance

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  1. Editorial Team
    Editorial Team
    2026-06-03T06:39:40+00:00Added an answer on June 3, 2026 at 6:39 am

    All other things being equal, the most-specific method will be called. From the JLS:

    15.12.2.5. Choosing the Most Specific Method

    If more than one member method is both accessible and applicable to a
    method invocation, it is necessary to choose one to provide the
    descriptor for the run-time method dispatch. The Java programming
    language uses the rule that the most specific method is chosen.

    The informal intuition is that one method is more specific than
    another if any invocation handled by the first method could be passed
    on to the other one without a compile-time type error.

    question.method(null) could mean either the String or Object overload, but since String is more specific (narrower) than Object, the String overload is the method that is called.

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