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Home/ Questions/Q 7711669
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Editorial Team
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Editorial Team
Asked: June 1, 20262026-06-01T01:26:02+00:00 2026-06-01T01:26:02+00:00

I was doing an assignment, tried simplifying code with same results. unsigned char x=5;

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I was doing an assignment, tried simplifying code with same results.

unsigned char x=5;
byte a1[100];
/*byte a1 is then filled*/
byte a2[7];
int counter = 0;

for (counter=0;counter!=8;counter++)
{
a2[counter]=a1[counter];
printf("%d ",x);
}

result is 5 5 5 5 5 5 5 ?
where ? is a random number

i’m confused why this is happening as the arrays do not even relate to this variable, and it seems that everything is in range for arrays. what could be causing this or how can i solve?

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  1. Editorial Team
    Editorial Team
    2026-06-01T01:26:03+00:00Added an answer on June 1, 2026 at 1:26 am

    You’re writing past the end of the array. Writing to a2[7] is undefined behaviour (and in your case, it wrote to the variable immediately after the array on the stack).

    To fix this, either end the loop at 7 or declare byte a2[8];.

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