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Home/ Questions/Q 815887
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T01:45:02+00:00 2026-05-15T01:45:02+00:00

I was doing some self-learning on how to pass data from JQuery Ajax to

  • 0

I was doing some self-learning on how to pass data from JQuery Ajax to a particular URL in CakePHP:
I have tested three sets of codes that the first one was working well, but the rest failed to work, which makes me so confused.
Could some experts here tell why the second and the third sets of codes failed to pass any data?

Set 1:

<input type=text name="data[User][name]" id="data[User][name]" size="36" maxlength="36"/>
var usr = $("#data\\[User\\]\\[name\\]").val();
$.post(
"http://www.washington.byethost18.com/site1/toavail/"+usr,
function(msg){alert(msg);}
);

Set 2:

<input type=text name="data[User][name]" id="data[User][name]" size="36" maxlength="36"/>
var usr = $("#data\\[User\\]\\[name\\]").val();
$.post(
"http://www.washington.byethost18.com/site1/toavail/",
 {queryString: ""+usr+""},
 function(msg){alert(msg);}
 );

Set 3:

<input type=text name="data[User][name]" id="data[User][name]" size="36" maxlength="36"/>
var usr = $("#data\\[User\\]\\[name\\]").val();
$.post(
"http://www.washington.byethost18.com/site1/toavail/",
 usr,
 function(msg){alert(msg);}
);
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-15T01:45:03+00:00Added an answer on May 15, 2026 at 1:45 am

    Because you wrote, that only the first version work, your server wait for the URL like

    http://www.washington.byethost18.com/site1/toavail/paramVal
    

    and not like

    http://www.washington.byethost18.com/site1/toavail/
    

    with “queryString=paramVal” or “paramVal” as posted data body. All three version send with the value usr variable in different way.

    A small remark: I recommend to use encodeURIComponent function to encode data which your send as a part of url.

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