Question

I was following a tutorial on PHP and HTML on how to use option=selected, but I am confused.

Here is my code:

<form name ="rating" method ="POST" action ="" /> 
<? echo "<input type = \"hidden\" name = accountID value = " . $row['accountID'] . ">";?>
<select name="rating">
    <? $values = array('','Very Bad','Bad','Average','Above Average');

    for ($i =0; $i < count($values); $i = $i + 1){
        echo "<option value = \"$i\"" . if ($rating == $i + 1) {echo "selected";} . "> $values[$i] </option>"; 
    }    
    ?>  
</select>
<input type ="Submit" name ="formSubmit" value ="Submit">
</form>    
<?

What I am trying to achieve is to have whatever option is stored in the database to be selected by default. What am I missing in the code?

Answer 1

try this out it will be what u want

  <form name ="rating" method ="POST" action ="" > <?php

echo "<input type = 'hidden' name = 'accountID' value = '" . $row['accountID'] . "' >";

?>
    <select name="rating">

        <? $values = array('','Very Bad','Bad','Average','Above Average');

        for ($i =0; $i < count($values); $i = $i + 1){ ?>
            <option value = "$i"  <?php if ($rating == $i + 1) {echo " selected='selected'" ;} ?> > $values[$i] </option>
          <?php 
        }

        ?>

        </select>
        <input type ="Submit" name ="formSubmit" value ="Submit" />
        </form>

    <?

EDIT:

yes this variable $rating is not defined . so try to define it like that

  if (isset $POST['rating']) {$rating = $POST['rating'];}else {$rating = 0 ;}

put it before this form somewhere inside php tag