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Home/ Questions/Q 6802423
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T19:13:18+00:00 2026-05-26T19:13:18+00:00

I was given a task, it’s nothing special but I did hit the wall

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I was given a task, it’s nothing special but I did hit the wall here…

After getting arithmetical means I need to compare them and output the highest and the lowest ones.

The x is a student number, the vid[] is the arithmetical mean.

For example:

Student number x has arithmetical mean vid[i]

and the task wants me to output which student has the highest and which one has the lowest means.

The worst part that I can’t use stuff like max() and min() because I don’t know how many students are there in total. Plus they are all arrays which have the same variable name vid[].

Any help would be appreciated =)

int main()
{
    int mokSK=0, p1[25], p2[25], p3[25], x[25], vid[25], iv=0;
    ifstream inFile("inFile.in");
    ofstream outFile("outFile.out");


    inFile >> mokSK;

    for(int i=0;i<mokSK;i++)
    {
        inFile >> x[i] >> p1[i] >> p2[i] >> p3[i];
        vid[i]=(p1[i]+p2[i]+p3[i])/3;
        outFile<< x[i] <<" " << vid[i] << endl;
    }

    return 0;
}
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-26T19:13:18+00:00Added an answer on May 26, 2026 at 7:13 pm

    If you want O(1) to access max and min graded students; from the beginning of reading, update your max and min graded student in each read pass.

    to be more clear: keep track of min and max graded student from the very beginning of the execution and update max and min graded students in each student data reading pass if needed.

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