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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T16:29:41+00:00 2026-05-11T16:29:41+00:00

I was goint through k & r. I was having problem in understanding following

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I was goint through k & r. I was having problem in understanding following lines on page 197(section A6)

Integral conversions: any integer is
converted to a given unsigned type by
finding the smallest non negative
value that is congruent to that
integer,modulo one more than the
largest value that can be represented
in the unsigned type.

Can any body explain this in a bit detail.
Thanks

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  1. Editorial Team
    Editorial Team
    2026-05-11T16:29:42+00:00Added an answer on May 11, 2026 at 4:29 pm

    any integer is converted to a given unsigned type by finding the smallest non negative value that is congruent to that integer,modulo one more than the largest value that can be represented in the unsigned type.

    Let’s take this bit by bit and from backwards:

    What is the largest value that can be represented in the unsigned type of width n bits?

    2^(n) - 1.
    

    What is one more than this value?

    2^n. 
    

    How does the conversion take place?

    unsigned_val = signed_val % 2^n
    

    Now, the why part: The standard does not mandate what bit representation is used. Hence the jargon. In a two’s complement representation — which is by far the most commonly used — this conversion does not change the bit pattern (unless there is a a truncation, of course).

    Refer to Integral Conversions from the Standard for further details.

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