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Asked: 2026-06-07T10:45:58+00:00

I was just playing with pointers and found this weird thing. I created the

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I was just playing with pointers and found this weird thing. I created the pointer p and displayed its address as I did in the following program, the address of p and &p is different, why are they different?

int main()
{
    int *p, s[5];
    cout << p <<endl;
    cout << &p <<endl;
    p = s;
    cout << p <<endl;
    cout << &p <<endl;
}
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1 Answer

  1. Editorial Team

    P is a pointer that means it holds an address to an integer. So when you print p it displays address of the integer it points to. Whereas when you print &p you are actually printing the address of p itself rather than the address it points to.

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