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I was just trying out Ruby and I came across String#to_i. Suppose I have this code:
var1 = '6 sldasdhkjas'
var2 = 'aljdfldjlfjldsfjl 6'
Why does puts var1.to_i output 6 when puts var2.to_i gives 0?
The
to_imethod returns the number that is formed by all parseable digits at the start of a string. Your first string starts with a with digit soto_ireturns that, the second string doesn’t start with a digit so 0 is returned. BTW, whitespace is ignored, so" 123abc".to_ireturns 123.