Question

I was looking for a way to create an array like:

[[1,1], [1,2], [1,3]
[2,1], [2,2], [2,3]
[3,1], [3,2], [3,3]]

For now I came up with this solution:

w=3 # or any int
h=3 # or any int
array = []
iw=1
while iw<=w do
  ih=1
  while ih <=h do
    array<<[iw, ih]
    ih+=1
  end#do
  iw+=1
end#do

But, I’m sure there must be a quicker way..?
This takes 1.107 seconds… (w=1900; h=1080)
Regards

EDIT:
I should’ve noticed that I’m stuck with 1.8.6..

Answer 1

This is similar to @nicooga’s answer, but I would use a range instead of manually creating the array (ie so you do not have to type each number for larger arrays).

range = (1..3).to_a
range.product(range)
#=> [[1, 1], [1, 2], [1, 3], [2, 1], [2, 2], [2, 3], [3, 1], [3, 2], [3, 3]]