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Home/ Questions/Q 62797
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Asked: May 10, 20262026-05-10T18:31:56+00:00 2026-05-10T18:31:56+00:00

I was making the following call: result = RegOpenKeyEx(key, s, 0, KEY_READ, &key); (C++,

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I was making the following call:

result = RegOpenKeyEx(key, s, 0, KEY_READ, &key); 

(C++, Visual Studio 5, Vista 64bit).

It is failing with error code 2 (‘File not found’) even though ‘regedit‘ shows that the key exists. This code has always worked on 32bit XP. Why is it ‘file not found’ when it clearly is there?

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  1. 2026-05-10T18:31:56+00:00Added an answer on May 10, 2026 at 6:31 pm

    I discovered that I could solve my problem using the flag: KEY_WOW64_64KEY , as in:

    result = RegOpenKeyEx(key, s, 0, KEY_READ|KEY_WOW64_64KEY, &key); 

    For a full explanation: 32-bit and 64-bit Application Data in the Registry

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