Question

I was messing around with some PHP codes and found this which baffles me

DisplayButton($width, $name, $url, $judge);

public function DisplayButton($width, $name, $url, $active = true)
{
if ($active)
{
  echo "<td width ='$width%'>
        <a href ='$url'>
        <img src ='s-logo.gif' alt ='$name' border ='0' /></a>
        <a href ='$url'><span class='menu'>$name</span></a></td>";
}  
else
{
  echo "<td width ='$width%'>
        <img src ='side-logo.gif'>
        <span class='menu'>$name</span></td>";
}  
}

how could you define a parameter like $active=true in this case, because as I believe that the value of the passed boolean variable $judge(either true or false) is going to be forced to change to true because of the $active= true, so how could it possibly reach to the else statement? I probably misunderstood the argument $active=true, but how? Thank you very much

Answer 1

Pass false, not true to reach that else block

$active = true at function declaration means that parameter is optional, so you can omit it while call the function. But if you pass it, then default value doesn’t affect in any way.