Question

I was performing JDBC select query in my web service to return some values from my database. Part of this table is attached to this question. After performing following query:

SELECT * FROM uses WHERE  uses_user_fk='22';

I receive only one row, but in database are two values that meet the query conditions, as you can see in attached picture. Can anyone tell me where I made a mistake. I’m using following JDBC instruction to execute the query

ResultSet tempResultSet = statement.executeQuery(query);

Bellow image of database table uses:

Below the compete method that query the database, argument query is the same as listed earlier “SELECT * FROM uses…”. I should add that the answer for that query is 4, I also try this query without using quotes (uses_user_fk=22) but the result was the same:

protected ArrayList<Integer> queryForIds(String query, String column) throws Exception {
        ArrayList<Integer> ids = new ArrayList<>();
        try {
            Class.forName("com.mysql.jdbc.Driver");
            connect = DriverManager
                    .getConnection(GeneralDatabaseConstants.DATABASE_CONNECTION_URL);
            statement = connect.createStatement();
            ResultSet tempResultSet = statement.executeQuery(query);
            if (tempResultSet.next())
                ids.add(new Integer(tempResultSet.getInt(column)));
        } catch (Exception e) {
            throw e;
        } finally {
            close();
        }
        return ids;
    }

Answer 1

replace

if (tempResultSet.next())

with

while (tempResultSet.next())