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Home/ Questions/Q 760027
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T15:40:03+00:00 2026-05-14T15:40:03+00:00

I was perusing section 13.5 after refuting the notion that built-in operators do not

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I was perusing section 13.5 after refuting the notion that built-in operators do not participate in overload resolution, and noticed that there is no section on operator->*. It is just a generic binary operator.

Its brethren, operator->, operator*, and operator[], are all required to be non-static member functions. This precludes definition of a free function overload to an operator commonly used to obtain a reference from an object. But the uncommon operator->* is left out.

In particular, operator[] has many similarities. It is binary (they missed a golden opportunity to make it n-ary), and it accepts some kind of container on the left and some kind of locator on the right. Its special-rules section, 13.5.5, doesn’t seem to have any actual effect except to outlaw free functions. (And that restriction even precludes support for commutativity!)

So, for example, this is perfectly legal:

#include <utility>
#include <iostream>
using namespace std;

template< class T >
T &
operator->*( pair<T,T> &l, bool r )
    { return r? l.second : l.first; }

template< class T >
 T & operator->*( bool l, pair<T,T> &r ) { return r->*l; }

int main() {
        pair<int, int> y( 5, 6 );
        y->*(0) = 7;
        y->*0->*y = 8; // evaluates to 7->*y = y.second
        cerr << y.first << " " << y.second << endl;
}

It’s easy to find uses, but alternative syntax tends not to be that bad. For example, scaled indexes for vector:

v->*matrix_width[2][5] = x; // ->* not hopelessly out of place

my_indexer<2> m( v, dim ); // my_indexer being the type of (v->*width)
m[2][5] = x; // it is probably more practical to slice just once

Did the standards committee forget to prevent this, was it considered too ugly to bother, or are there real-world use cases?

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  1. Editorial Team
    Editorial Team
    2026-05-14T15:40:03+00:00Added an answer on May 14, 2026 at 3:40 pm

    Googling around a bit, I found more instances of people asking whether operator->* is ever used than actual suggestions.

    A couple places suggest T &A::operator->*( T B::* ). Not sure whether this reflects designer’s intent or a misimpression that T &A::operator->*( T A::* ) is a builtin. Not really related to my question, but gives an idea of the depth I found in online discussion & literature.

    There was a mention of “D&E 11.5.4” which I suppose is Design and Evolution of C++. Perhaps that contains a hint. Otherwise, I’m just gonna conclude it’s a bit of useless ugliness that was overlooked by standardization, and most everyone else too.

    Edit See below for a paste of the D&E quote.

    To put this quantitatively, ->* is the tightest binding operator that can be overloaded by a free function. All the postfix-expression and unary operators overloads require nonstatic member function signatures. Next precedence after unary operators are C-style casts, which could be said to correspond to conversion functions (operator type()), which also cannot be free functions. Then comes ->*, then multiplication. ->* could have been like [] or like %, they could have gone either way, and they chose the path of EEEEEEVIL.

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