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Home/ Questions/Q 710063
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T04:34:23+00:00 2026-05-14T04:34:23+00:00

I was playing around with recursion and did this simple function. I was assuming

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I was playing around with recursion and did this simple function. I was assuming that it would print out 9-0 to stdout, but, it prints 0-9. I can’t see how that happens at all.

int main()
{
        rec(10);
        return 0;
}

int rec(int n){
        if(n > 0)
                printf("%d\n", rec(n -1));
        return n;
}
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  1. Editorial Team
    Editorial Team
    2026-05-14T04:34:23+00:00Added an answer on May 14, 2026 at 4:34 am

    As Michael Burr says in the comments, if you want to see what’s going on, compile with debugging symbols enabled, like this:

    gcc -o test -g test.c
    

    Then run with gdb like so.

    gdb test
    

    Then, to start things going, type

    start
    

    Which breaks at the first call in the main function. Type

    step
    

    to get to the next line in the code, and from then on, just press enter to keep repeating the last command. If you’re happy, type continue to stop stepping through. You’ll see the values and evaluated lines at each stage which’ll confirm the above answers.

    Hope that provides some useful info.

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