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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T12:34:20+00:00 2026-05-13T12:34:20+00:00

I was reading a StackOverFlow post regarding sorting a vector of pairs by the

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I was reading a StackOverFlow post regarding sorting a vector of pairs by the second element of the pair. The most obvious answer was to create a predicate, but one answer that used boost caught my eye.

std::sort(a.begin(), a.end(), 
  boost::bind(&std::pair<int, int>::second, _1) <
  boost::bind(&std::pair<int, int>::second, _2));

I’ve been trying to figure out how boost::bind works, or at least just how to use it, but I can’t figure out what the purpose of the placeholder arguments _1 and _2 are, and the boost documentation doesn’t sink in at all.

Could anyone explain this specific usage of boost::bind?

P.S. Original question: How do I sort a vector of pairs based on the second element of the pair?

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  1. Editorial Team
    Editorial Team
    2026-05-13T12:34:21+00:00Added an answer on May 13, 2026 at 12:34 pm

    This expression:

    boost::bind(&std::pair<int, int>::second, _1) <
    boost::bind(&std::pair<int, int>::second, _2)
    

    namely, the use of the < operator actually defines a functor between two other functors, both of which defined by bind.

    The functor expected by sort needs to have an operator() which looks like this:

    bool operator()(const T& arg1, const T& arg2);
    

    when you’re creating a functor using boost’s < then the name holders _1 and _2 correspond to arg1 and arg2 of the functor you’re creating.

    The bind call create a functor that calls ::second of arg1 and arg2

    With any luck, the introduction of lambdas in C++0x will make expressions like this obsolete.

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