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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T00:20:33+00:00 2026-05-27T00:20:33+00:00

I was reading about floating-point representation and underflow/overflow and I ecnountered something interesting –

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I was reading about floating-point representation and underflow/overflow and I ecnountered something interesting – gradual underflow. As I understand gradual underflow means that the result of, for example substraction x-y is so small that it could be flushed to 0 but floating-point system produces number that is smaller then UFL. Everywhere I read that it is made by losing some precission, it means that some bits of mantissa goes to exponent so we can have smaller exponent?

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  1. Editorial Team
    Editorial Team
    2026-05-27T00:20:34+00:00Added an answer on May 27, 2026 at 12:20 am

    Effectively the answer is yes — the bits of the mantissa go to the exponent. These are called subnormal (AKA denormal) numbers. For example, in IEEE double-precision, the smallest power of two exponent for a normal number — a number with a full 53 bits of precision — is 2-1022. But powers of two up to 2-1074 can effectively be represented, as dictated by the location of the first 1 bit in the unnormalized significand. So exponent 2-1023 has 52 bits of precision, 2-1024 has 51 bits of precision, … , 2-1074 has 1 bit of precision.

    (See my article What Powers of Two Look Like Inside a Computer to visualize this better.)

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