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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T07:01:01+00:00 2026-06-17T07:01:01+00:00

I was reading the definition for the Eq typeclass in the Data library, and

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I was reading the definition for the Eq typeclass in the Data library, and I’m confused. At what point is it realized that two values are equal or not equal. From what I see, it looks like they would just call each other ad infinitum.

It’s defined as so:

class  Eq a  where
    (==), (/=)           :: a -> a -> Bool

    x /= y               = not (x == y)
    x == y               = not (x /= y)

Would somebody mind explaining where it realizes the Bool value? Are they even calling each other, or is something else going on?

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  1. Editorial Team
    Editorial Team
    2026-06-17T07:01:03+00:00Added an answer on June 17, 2026 at 7:01 am

    That’s the default implementation of those methods, and yes, it is circular. If you use them as-is, you’ll loop:

    data Foo = Foo
    instance Eq Foo
    
    > Foo == Foo
    ^CInterrupted
    

    The circular definitions exist so you can implement (==) and get (/=) for free, or vice versa:

    data Foo = Foo
    instance Eq Foo where
      x == y = True
    
    > Foo /= Foo
    False
    

    See also the Ord class, which explains what the minimal complete definition is in that particular case.

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