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Home/ Questions/Q 8139093
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Editorial Team
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Editorial Team
Asked: June 6, 20262026-06-06T11:42:37+00:00 2026-06-06T11:42:37+00:00

I was reading the Dutch national flag problem , but couldn’t understand what the

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I was reading the Dutch national flag problem, but couldn’t understand what the low and high arguments are in the threeWayPartition function in the C++ implementation.

If I assume them as min and max elements of the array to be sorted, then the if and else if statements doesn’t makes any sense since (data[i] < low) and (data[i] > high) always returns zero.

Where am I wrong?

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  1. Editorial Team
    Editorial Team
    2026-06-06T11:42:38+00:00Added an answer on June 6, 2026 at 11:42 am

    low and high are the values you have defined to do the three-way partition i.e. to do a three-way partition you only need two values:

    [bottom] <= low  < [middle] < high <= [top]
    

    In the C++ program what you are moving are the positions where the partitions occurred. A step-by-step example:

    data = [ 3, 1, 4, 9, 8, 2, 6, 9, 0 ]
    low  = 4
    high = 8
    

       [ 3 , 1 , 4 , 9 , 8 , 2 , 6 , 9 , 0 ]
    p^  i^                                  q^
    

       [ 3 , 1 , 4 , 9 , 8 , 2 , 6 , 9 , 0 ]
        p^  i^                              q^
    

       [ 3 , 1 , 4 , 9 , 8 , 2 , 6 , 9 , 0 ]
            p^  i^                          q^
    

       [ 3 , 1 , 4 , 9 , 8 , 2 , 6 , 9 , 0 ]
            p^      i^                      q^
    

       [ 3 , 1 , 4 , 0 , 8 , 2 , 6 , 9 , 9 ]
            p^      i^                  q^
    

       [ 3 , 1 , 0 , 4 , 8 , 2 , 6 , 9 , 9 ]
                p^      i^              q^
    

       [ 3 , 1 , 0 , 4 , 9 , 2 , 6 , 8 , 9 ]
                p^      i^          q^
    

       [ 3 , 1 , 0 , 4 , 6 , 2 , 9 , 8 , 9 ]
                p^      i^      q^
    

       [ 3 , 1 , 0 , 4 , 6 , 2 , 9 , 8 , 9 ]
                p^          i^  q^
    

       [ 3 , 1 , 0 , 2 , 6 , 4 , 9 , 8 , 9 ]
                    p^         iq^
    

    As the algorithm says you:

    • Swap the element above the bottom (i.e. p + 1) because everything below the bottom has been already checked, or
    • Swap the element below the top (i.e. q - 1) because everything above the top has been already checked, or
    • Leave the element where it is because it belongs to middle.

    You get [3, 1, 0, 2], [6, 4] and [9, 8, 9] as bottom, middle and top partitions respectively.

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