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Home/ Questions/Q 7550141
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T10:08:14+00:00 2026-05-30T10:08:14+00:00

I was reading the Dynamic, typesafe queries in JPA 2.0 article and stumbled upon

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I was reading the “Dynamic, typesafe queries in JPA 2.0” article and stumbled upon this example:

EntityManager em = ...
CriteriaBuilder qb = em.getCriteriaBuilder();
CriteriaQuery<Person> c = qb.createQuery(Person.class);
Root<Person> p = c.from(Person.class);
Predicate condition = qb.gt(p.get(Person_.age), 20);
//                                     ^^ --- this one
c.where(condition);
TypedQuery<Person> q = em.createQuery(c); 
List<Person> result = q.getResultList();

I was wondering, what exactly does the underscore here mean?

Since an underscore it is a valid part of a classname I don’t understand why this can be used in JPA.
I checked this with an existing entity in my code and of course my class couldn’t be resolved as ClassName_

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  1. Editorial Team
    Editorial Team
    2026-05-30T10:08:16+00:00Added an answer on May 30, 2026 at 10:08 am

    That is the metamodel for the persistance. It is how you can do type safe JPA queries in Java. It allows queries to staticly check your queries because classBar_ describes your JPA Bar. In HQL, you can easily mistype a query and not know it until it is run.

    So technically, the _ does not mean anything, but it is the convention used by JPA to name a metamodel class of a JPA persistent model class. Model_ is the metamodel of Model, and it provides the names of the queryable fields and their types.

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