Question

I was recently asked to write a program, that determines whether a number is even or odd without using any mathematical/bitwise operator!

Any ideas?

Thanks!

Answer 1

This can be done using a 1 bit field like in the code below:

#include<iostream>

struct OddEven{
    unsigned a : 1;
};
int main(){
    int num;
    std::cout<<"Enter the number: ";
    std::cin>>num;
    OddEven obj;
    obj.a = num;
    if (obj.a==0)
        cout<<"Even!";
    else
        cout<<"Odd!";
    return 0;
}

Since that obj.a is a one-field value, only LSB will be held there! And you can check that for your answer.. 0 -> Even otherwise Odd..!!