Question

I was recently reading a few articles on PHP Object oriented programming and came across something like this:

class a {}
$temp = new a();
$temp->newfiled = 20;    // This field is not present within the class

The above code works fine in PHP 5.3

Why dosent PHP throw an error? I am coming from Java background in which we can only use fields that have been defined within a class.

Update: Edited php.ini to error_reporting = E_ALL | E_STRICT, but it continues to hide errors.

Also, is this a feature of PHP?

Answer 1

In short: PHP is not Java. Slightly longer: PHP is dynamic type, whereas Java is a static typed language.
However, you could raise your error-level. You should see a notice, or (strict-)warning.

http://php.net/language.oop5.properties