Question

I was retrieving some date records from my database with the following results:

Date
09/18/2012 1:34:34 AM
09/8/2012 8:15:34 AM
09/8/2012 12:02:11 AM
08/30/2012 8:47:02 PM
08/29/2012 11:44:00 PM

As from the list above, there are 2 dates with 09/8/2012 that I would like to select 09/8/2012 8:15:34 AM (the later one), thus my result will look like this:

Date
09/18/2012 1:34:34 AM
09/8/2012 8:15:34 AM
08/30/2012 8:47:02 PM
08/29/2012 11:44:00 PM

How can I go about doing this? Thanks in advance 🙂

Answer 1

select max(date_column)
from table
group by trunc(date_column)
order by 1