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Home/ Questions/Q 7399255
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Editorial Team
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Editorial Team
Asked: May 29, 20262026-05-29T04:02:13+00:00 2026-05-29T04:02:13+00:00

I was studying an open source code where I came across the following line

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I was studying an open source code where I came across the following line

stringBytes[i] = (byte) (stringChars[i] & 0x00FF);

Can someone explain what is actually happening in this line ???

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  1. Editorial Team
    Editorial Team
    2026-05-29T04:02:14+00:00Added an answer on May 29, 2026 at 4:02 am

    Char consists of 2 bytes in Java and of course byte is single byte.

    So in this operation:

    stringBytes[i] = (byte) stringChars[i] & 0x00FF
    

    A char value (16 bits) is being binary ANDED with number 0x00FF (binary: 0000 0000 1111 1111) to make it one byte.

    By binary ANDING with 8 0s and 8 1s you’re basically masking off 8 left most OR most significant bits (MSB) of the char value thus leaving only 8 right most or least significant bits (LSB) intact. Then code is assigning resulting values to a byte by using cast (byte), which is otherwise an int value.

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