Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 3272070
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 17, 20262026-05-17T18:47:21+00:00 2026-05-17T18:47:21+00:00

I was thinking that dynamic arrays were a replacement for vectors in D, but

  • 0

I was thinking that dynamic arrays were a replacement for vectors in D, but it seems they have no remove function (only associative arrays do) which is rather a limitation for a vector so I’m wondering if I’ve got that right. If a have an array like follows,

uint[] a;
a.length = 3;
a[0] = 1;
a[1] = 2;
a[2] = 3;

Then the only way I’ve found to remove, say, the second element is,

a = a[0..1] ~ a[2];

But that doesn’t seem right (but maybe only because I don’t understand this all yet). So is there a vector and is there another way of removing an element from a dynamic array?

Thanks.

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-17T18:47:22+00:00Added an answer on May 17, 2026 at 6:47 pm

    You could use std.algorithm.remove(), which works not only with arrays but with generic ranges. Example:

    import std.algorithm;
    
    void main() {
        uint[] a = [1, 2, 3];
        a = a.remove(1);
        assert(a == [1, 3]);
    }
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a dilemna that needs I've been thinking a while but still haven't
Thinking that the answer to this is pretty obvious but here it goes: When
I was thinking that I would have two tables for mysql. One for storing
I was thinking that at the top of my partial I would have something
Am I correct in thinking that that Python doesn't have a direct equivalent for
Am I correct in thinking that if I have a WCF OperationContract takes in
Let's say that any C function has a pointer already declared, but not assigned
I've been thinking about setting up a dynamic image grid similiar to milliondollarhomepage, but
I have a page that needs to create dynamic form fields as often as
I have a page that has 2 columns. The first column is a dynamic

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.