Question

I was trying a program with GDB, I did a ‘break x’ and then was running step by step. So when I want to quit, I would say ‘quit’, it would return an ‘inferior process will be killed warning message’. What happens if I do ‘Y’. Because I want to somehow come out of the process. And what would happen If I attach a running process and quit. Will it be detached or the running process will be exited? Different sources give different ideas. Please advise.

Also, when I try to run a program it says, and I am running the standard program from peter’s tutorial. It gives this error when I do an step to line 16.

 _IO_puts (str=0x40075e "In display():") at ioputs.c:35
 35 ioputs.c: No such file or directory.
     in ioputs.c

Program

  14 void display(int z, int *zptr) {
  15        printf("In display():\n");
  **16       printf("   z is %d and is stored at %p.\n", z, &z);**
  17       printf("   zptr points to %p which holds %d.\n", zptr, *zptr);
  18   }

Answer 1

If you run the process in the debugger and quit the debugger, the running program is killed (just as you would with SIGKILL). To end the program normally, say continue (possibly with a number large of ignores) until the program is done.

If you attach the debugger to a running program and exit the debugger, the debugger will just detach and the program continues running, unless you kill it beforehand.