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Editorial Team
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Editorial Team
Asked: June 7, 20262026-06-07T17:22:18+00:00 2026-06-07T17:22:18+00:00

I was trying to convert basic Javascript function into PHP, and I saw that

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I was trying to convert basic Javascript function into PHP, and I saw that one of the variables was declared var Variable = new Array (13).

I know that PHP variables are declared like: $variable = array()

but what about the “13” in new Array(13)? does that translate to $variable = array(13)? I’ve tried that but it didn’t seem to work.

This in Javascript

var results = new Array (13);

becomes this in PHP, am I correct?

$results = array(13);
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  1. Editorial Team
    Editorial Team
    2026-06-07T17:22:20+00:00Added an answer on June 7, 2026 at 5:22 pm

    Actually, in this context, you’re creating an array of size 13.

    You don’t really need to preallocate arrays in PHP, but you can do something like:

    $result = array_fill( 0, 12, null);
    

    This will create an array with 13 elements (indexes 0 through 12) whose values are null.

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