I was trying to learn java and when I went through access specifiers I had a doubt. What is the difference between the default one if none is specified and the protected access specifier in java?
Share
Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.
Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Please briefly explain why you feel this question should be reported.
Please briefly explain why you feel this answer should be reported.
Please briefly explain why you feel this user should be reported.
The
protectedspecifier allows access by all subclasses of the class in question, whatever package they reside in, as well as to other code in the same package. The default specifier allows access by other code in the same package, but not by code that is in subclasses residing in different packages. See Java Language Specification Section 6.6.EDIT: Per request of Michael Schmeißer (so others don’t have to read through the comments or follow a link to find this): all members of interfaces are implicitly public. It is, in fact, a compile-time error to specify any access specifier for an interface member other than
public(although no access specifier at all defaults to public access). Here’s the full set of rules from the JLS for class members (see the above link for the rules for packages, top-level classes and interfaces, and arrays):