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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T06:21:00+00:00 2026-05-13T06:21:00+00:00

I was trying to make a tail-recursive version of this very simple SML function:

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I was trying to make a tail-recursive version of this very simple SML function:

fun suffixes [] = [[]]
  | suffixes (x::xs) = (x::xs) :: suffixes xs;

During the course of this, I was using type annotations on the paramaters. The following code shows this, and causes a type error (given below), whereas if I simply remove the type annotations, SML accepts it with no problem, giving the whole function the same signature as the simpler function above.

fun suffixes_tail xs =
    let
        fun suffixes_helper [] acc = []::acc
          | suffixes_helper (x::xs:'a list) (acc:'b list) =
                suffixes_helper xs ((x::xs)::acc)
    in
        suffixes_helper xs []
    end;

Error:

$ sml typeerror.sml 
Standard ML of New Jersey v110.71 [built: Thu Sep 17 16:48:42 2009]
[opening typeerror.sml]
val suffixes = fn : 'a list -> 'a list list
typeerror.sml:17.81-17.93 Error: operator and operand don't agree [UBOUND match]
  operator domain: 'a list * 'a list list
  operand:         'a list * 'b list
  in expression:
    (x :: xs) :: acc
typeerror.sml:16.13-17.94 Error: types of rules don't agree [UBOUND match]
  earlier rule(s): 'a list * 'Z list list -> 'Z list list
  this rule: 'a list * 'b list -> 'Y
  in rule:
    (x :: xs : 'a list,acc : 'b list) =>
      (suffixes_helper xs) ((x :: xs) :: acc)
/usr/local/smlnj-110.71/bin/sml: Fatal error -- Uncaught exception Error with 0
 raised at ../compiler/TopLevel/interact/evalloop.sml:66.19-66.27

There are two errors given. The latter seems to be less important here, a mismatch between the two clauses of suffixes_helper. The first is the one I don’t understand. I annotate to state that the first param is of type 'a:list and that the second param is of type 'b:list. Should not the Hindley-Milner type inference algorithm, which is built of top of general unification as I understand it, be able to unify 'b:list with 'a:list list, using a substitution of 'b ---> 'a list?

EDIT: An answer suggests it may have something to do with the type inference algorithm disallowing inferred types which in some sense are more strict than the ones given by the type annotations. I would guess that such a rule would only apply to annotations on parameters and on a function as a whole. I have no idea if this is correct. In any case, I tried moving the type annotations over to the function body, and I get the same sort of error:

fun suffixes_helper [] acc = []::acc
    | suffixes_helper (x::xs) acc =
          suffixes_helper (xs:'a list) (((x::xs)::acc):'b list);

The error is now:

typeerror.sml:5.67-5.89 Error: expression doesn't match constraint [UBOUND match]
  expression: 'a list list
  constraint: 'b list
  in expression:
    (x :: xs) :: acc: 'b list
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-13T06:21:01+00:00Added an answer on May 13, 2026 at 6:21 am

    I am not sure about SML, but F#, another functional language, gives a warning in this kind of situation. Giving an error may be a bit harsh, but it makes sense: if the programmer introduces an extra type variable ‘b, and if ‘b must be of type ‘a list, the function might not be as generic as the programmer intended, which is worth reporting.

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