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Home/ Questions/Q 6948719
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T13:51:35+00:00 2026-05-27T13:51:35+00:00

I was trying to make my code smaller by caching functions to variables. For

  • 0

I was trying to make my code smaller by caching functions to variables. For example:

function test(){
   var a = Array.prototype.slice,
   b = a.call(arguments);
   // Do something
   setTimeout(function(){
     var c = a.call(arguments);
     // Do something else
   }, 200);
}

So instead of calling Array.prototype.slice.call(arguments), I can just do a.call(arguments);.

I was trying to make this even smaller by caching Array.prototype.slice.call, but that wasn’t working.

function test(){
   var a = Array.prototype.slice.call,
   b = a(arguments);
   // Do something
   setTimeout(function(){
     var c = a(arguments);
     // Do something else
   }, 200);
}

This gives me TypeError: object is not a function. Why is that?

typeof Array.prototype.slice.call returns "function", like expected.

Why can’t I save .call to a variable (and then call it)?

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  1. Editorial Team
    Editorial Team
    2026-05-27T13:51:36+00:00Added an answer on May 27, 2026 at 1:51 pm

    Function.prototype.call is an ordinary function that operates on the function passed as this.

    When you call call from a variable, this becomes window, which is not a function.
    You need to write call.call(slice, someArray, arg1, arg2)

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